MATHEMATICS-III (DIFFERENTIAL CALCULUS)
Instructions:
- The marks are indicated in the right-hand margin.
- There are NINE questions in this paper.
- Attempt FIVE questions in all.
- Question No. 1 is compulsory.
The solution of the differential equation y″ − 3y′ + 2y = e3x
The solution of p + q = z is
The series 1 − (1/(1!)2)(x/2)2 + (1/(2!)2)(x/2)4 − (1/(3!)2)(x/2)6 + … is
If ∫−11 Pn(x) dx = 2, then n is
The particular solution of y″ + 9y′ = sin 3x is
The differential equation y″ + (s3 sin x)5y′ + y = cos x3 is
The magnitude of the directional derivative of the function f(x, y) = x2 + 3y2 in a direction normal to the circle x2 + y2 = 2, at the point (1,1) is
If R = xi + yj + zk is the position vector, then div R is
The degree of the homogeneous function f(x, y) = (x7/3 + y7/3)/(x + y) is
If f(x, y) = tan−1 y/x + sin−1 x/y, then x∂f/∂x + y∂f/∂y =
If y1/m + y−1/m = 2x, prove that
(i) (x2 − 1)y2 + xy1 − m2y = 0
(ii) (x2 − 1)yn+2 + (2n + 1)xyn+1 + (n2 − m2)yn = 0If p2 = a2 cos2θ + b2 sin2θ, prove that p + d2p/dθ2 = a2b2/p3
Use Taylor’s theorem to expand f(x, y) = xy in powers of (x − 1) and (y − 1).
Find the dimension of the rectangular box, open at the top, of maximum capacity whose surface area is 432 sq.cm.
If u = tan−1(y2/x), prove that x2 ∂2u/∂x2 + 2xy ∂2u/∂x∂y + y2 ∂2u/∂y2 = −sin2u · sin 2u
If by the substitution u = x2 − y2, v = 2xy, f(x, y) = θ(u, v), show that ∂2f/∂x2 + ∂2f/∂y2 = 4(x2 + y2)(∂2θ/∂u2 + ∂2θ/∂v2)
Verify Stoke’s theorem for F = (2x − y)i − yz2j − y2zk over the upper half surface x2 + y2 + z2 = 1, bounded by its projection on the xy −plane.
If the directional derivative of φ = ax2y + by2z + cxz2 at the point (1,1,1) has maximum magnitude 15 in the direction parallel to the line (x − 1)/2 = (y − 3)/(−2) = z, find the values of a, b, c
Solve (x2 + y2)(x dx + y dy) = a2(x dy − y dx)
Solve p(p + x) = y(x + y)
Solve (2y log y + y − x)dy = y dx
Solve, by the method of variation of parameters, y″ − 2y′ + y = ex log x.
Solve x2 d2y/dx2 − 3x dy/dx + y = log x · (sin(log x) + 1)/x
Prove that Jm(x) = (1/π) ∫0π cos(mθ − x sin θ) dθ, where ’n’ is positive integer
Solve the equation : (z2 − 2yz − y2)p + (xy + zx)q = xy − zx.
Solve the equation : (x − y)(px − qy) = (p − q)2
